## Analysis of Michaelis-Menten Kinetics Statements ### Correct Statements (Options 0, 1, 3) **Option 0 — Km definition:** - Km = (k₋₁ + k₂) / k₁, where k₋₁ and k₂ are rate constants - Km is **enzyme-specific** and substrate-specific, NOT dependent on enzyme concentration - At [S] = Km, velocity = Vmax/2 (half-maximal velocity) - This is a fundamental definition and **always correct** **Option 1 — Vmax proportionality:** - Vmax = k₂ × [E]total (where k₂ is the turnover number) - Vmax is **directly proportional** to total enzyme concentration - This is why enzyme assays rely on measuring Vmax - **Correct statement** **Option 3 — Lineweaver-Burk plot:** - The reciprocal form: $\frac{1}{v} = \frac{Km}{Vmax} \cdot \frac{1}{[S]} + \frac{1}{Vmax}$ - This is a **linear equation** (y = mx + b form) - Allows graphical determination of Km (x-intercept = -1/Km) and Vmax (y-intercept = 1/Vmax) - **Correct statement** ### Incorrect Statement (Option 2) — THE ANSWER **Option 2 — Order of reaction at low [S]:** - When [S] << Km, the denominator in the Michaelis-Menten equation becomes approximately equal to Km - $v ≈ \frac{Vmax \cdot [S]}{Km}$ (simplified form) - Since Km is constant, v is **directly proportional to [S]** - This means the reaction follows **first-order kinetics** (not zero-order) with respect to substrate - Zero-order kinetics occurs when [S] >> Km (enzyme is saturated) - **This statement is FALSE** ### Key Kinetic Regimes | Substrate Concentration | Kinetic Order | Velocity Behavior | |---|---|---| | [S] << Km | First-order (pseudo-unimolecular) | v ∝ [S]; linear increase | | [S] ≈ Km | Mixed order | v = Vmax/2; Michaelis-Menten applies | | [S] >> Km | Zero-order | v ≈ Vmax; independent of [S] | **Key Point:** The **order of the reaction changes with substrate concentration**. Low [S] gives first-order kinetics; high [S] gives zero-order kinetics. **High-Yield:** This is a classic NEET PG trap — students confuse the kinetic regimes. Remember: **saturation → zero-order; starvation → first-order**. **Mnemonic:** "**S**mall [S] = **S**econd-order (actually first-order); **S**aturated [S] = **Z**ero-order" — helps anchor the opposite behavior. [cite:Lehninger Principles of Biochemistry Ch 8]
Sign up free to access AI-powered MCQ practice with detailed explanations and adaptive learning.